[(3+5i)-(3-2i)]+(8+i)=0

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Solution for [(3+5i)-(3-2i)]+(8+i)=0 equation:


Simplifying
[(3 + 5i) + -1(3 + -2i)] + (8 + i) = 0

Remove parenthesis around (3 + 5i)
[3 + 5i + -1(3 + -2i)] + (8 + i) = 0
[3 + 5i + (3 * -1 + -2i * -1)] + (8 + i) = 0
[3 + 5i + (-3 + 2i)] + (8 + i) = 0

Reorder the terms:
[3 + -3 + 5i + 2i] + (8 + i) = 0

Combine like terms: 3 + -3 = 0
[0 + 5i + 2i] + (8 + i) = 0
[5i + 2i] + (8 + i) = 0

Combine like terms: 5i + 2i = 7i
[7i] + (8 + i) = 0
[7i] + (8 + i) = 0

Remove parenthesis around (8 + i)
[7i] + 8 + i = 0

Reorder the terms:
8 + [7i] + i = 0

Combine like terms: [7i] + i = 8i
8 + 8i = 0

Solving
8 + 8i = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 8i = 0 + -8

Combine like terms: 8 + -8 = 0
0 + 8i = 0 + -8
8i = 0 + -8

Combine like terms: 0 + -8 = -8
8i = -8

Divide each side by '8'.
i = -1

Simplifying
i = -1

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